**Question 1**

Question 2

Suppose you were given the task of estimating the density of two plant species in a field. Based on the life histories of the two species, you expect that the spatial distribution of one of the species is approximately uniform, whereas the other is likely to be clumped. How might your approach to estimating the density of these two species differ? Species distribution Species distribution is the arrangement of a particular taxon dispersal and the spatial arrangement of this. These distributions are limited by their “range” aka the geographic limits of the population as well as resource availability within these particular areas.

Question 3

Suppose you are asked to assist in the design of an earthen-lined drainage canal. The ground comprised of clay which can support the relativity steep side-walls shown in the figure. At the canal’s maximum capacity the flowrate can be no greater than 160 cfs (to avoid eroding the canal walls). The task of determining the maximum bottom slope of the canal falls on you. You may assume that the flow through the canal remains free if weeds and debris.

Find the bottom slope of canal for 160 cfs at maximum capacity and how many feet of fall this corresponds to over one mile.

**Answer to question 1**

Answer to question 2

When species are distributed in uniform fashion ones samples can be chosen randomly from the large population. Since the distribution is spread evenly cross their range the sums of counts found in research can simply be divided by the total area of the range.

When species are distributed in a clumped fashion intensive sampling should be done so that many small samples can be accurately modelled. If the clumped samples are clustered in equally sized areas random clustered sampling should be done. If these clusters are not equal in size than probability proportionate to size sampling should be done.

Answer to question 3

Given data

The maximum flow rate should not greater than 16. cfs.

Let us assume the chezy s constant for channel, C is 76.

Calculate the bottom slope of channel for 160 cfs at maximum capacity.