Question 1
If the most efficient of all cross sections can be used, what shape and size of open channel would you recommend to carry 300 cfs with a velocity of 7 ft per second? Draw a representative figure for each part of your solution. For this problem, study the 4 possible cross sections and defend your final recommendation. Assume logical frictional/roughness parameters depending on the equation you choose to use. Your final output must be a construction drawing of your recommended cross section.
Question 2
If the most efficient of all cross sections can be used, what shape and size of open channel would you recommend to carry 300 cts with a velocity of 7 fi per second? Draw a representative figure for each part of your solution. For this problem. study the 4 possible cross sections and defend your final recommendation. Assume logical frictional/roughness parameters depending on the equation you choose to use. Your final output must be a construction drawing of your recommended cross section.
Question 3
If the most efficient of all cross sections can be used, what shape and size of open channel would you recommend to carry 300cfs with a velocity of 7 ft per second
Answer to question 1
If the most efficient of all cross sections can be used,what shape and size of open channel would you recommend to carry 300 cfs with a velocity of 7 ft per second? Draw representative figure for each part of your solution
Hence B = 5.8 fts and y = 5fts
Answer to question 2
Answer to question 3
Step 1 Introduction:-
In an open channel flow condition, the Hydraulically efficient channel section is defined s the section in which the conveyance of a channel section of a given area increases with a decrease in its perimeter. Most economic channel section is defined as the section in which the discharge is maximum with a given minimum wetted perimeter of the section. The best section provides the best conveyance with the minimum perimeter in the given area.
Step 2Calculation:-
Selecting the rectangular section channel for the flow in the above problem.
Since we know that the discharge is equal to the product of area and velocity so mathematically,
Step 3Conclusion:-
