**Question 1**

Question 2

-0.59 find the probability of z occuring in the indicated region

Question 3

Find the probability of z occurring in the indicated region -1.33

Shaded region to the right

Answer to question 1

Since, you have asked multiple question, we will solve the first question for you. If you want any specific question to be solved then please specify the question number or post only that question.

The required probability of *z* occurring in the indicated region of the standard normal distribution can be obtained as:

Answer to question 2

Using excel fuction normsdist(-0.59) we get as follows:

P(Z<-0.59)= 0.2776

P(Z>-0.59) 0.7224

Answer to question 3

Using a table/technology, the left tailed area of this is

P(z < -1.33 ) = 0.091759136

Thus, the right tailed area is the complement,

P(z > -1.33 ) = 0.908240864 [ANSWER]