A semipermeable membrane is placed between the following solutions. Which solution will decrease in volume?
Solution A: 4 % (m/v) starch
Solution B: 4.94 % (m/v) starch
A semipermeable membrane is placed between the following solutions. Which solution will increase in volume?
Learning Goal: Part A To learn about osmosis and about isotonic solutions, hypertonic solutions, and hypotonic solutions. A semipermeable membrane is placed between the following solutions. Which solution will decrease in volume? Osmosis is the net movement of water across a semipermeable membrane from an area of lower concentration to an area of higher concentration. • View Available Hint(s) (Figure 1) O Solution A: 1.81 % (m/v) starch The water will continue to move across the O Solution B: 6.89 % (m/v) starch semipermeable membrane as the system attempts to reach equilibrium, where both solutions have the same concentration. Submit There are three different ways a solution can be described in relation to a cell placed in the solution: isotonic, hypotonic, and hypertonic. Compared to a cell, an isotonic solution exerts the same osmotic pressure as the cellular fluids. In other words. it Part B A semipermeable membrane is placed between the following solutions. Which solution will increase in volume? Figure < 1 of 1 > View Available Hint(s) Semipermeable membrane O Solution C: 7.40 % NaCl Pure HO NaCl(aq) O Solution D: 14.6 % NaCl Submit H2O- Time H2O H2O -HO Part C A red blood cell has been placed into each of three different solutions. One solution is isotonic to the celI, one solution is hypotonic to the cell, and one solution is hypertonic to the cell. Sort each beaker into the appropriate bin based on the cel reaction in each solution.
Answer to question 1
The volume of solution A will decrease.
Solution B has a higher concentration than solution A. The tendency of the solvent molecules is to move to an area with a higher concentration of solute in order to reach an equilibrium concentration. The movement of the solvent from solution A to solution B results in the reduction of volume of solution A.
Answer to question 2
This is an example of osmosis process.
Solution A is 4 % (m/V) starch solution and solution B is 4.94 % ( m/v) solution.
Solution B is more concentrated than solution A. Therefore, solvent molecules form solution A will flow to the solution B. Therefore, volume of solution A will decrease and that of solution B will increases.
ANSWER : Solution 4 % ( m/V) starch solution.
Solution C is 5.17 % NaCl solution and Solution D is 14 % NaCl solution.
Solution D is more concentrated than solution C. Therefore, solvent molecules form solution C will flow to the solution D. As a result, volume of solution C will decrease and that of solution D will increase.
ANSWER : Solution D 14 % NaCl solution.
Answer to question 3
When a semipermeable membrane is placed between two solutions of different concentrations the solvent flows from the solution with a lower concentration to the solution with a higher concentration. As a result the volume of the solution with lower concentration decreases and the volume of the solution with higher concentration increases.
From the principle in step one, we can solve the given questions
The volume of solution A with 1.81 % (m/v) starch decreases.
The volume of solution D with 14.6% NaCl increases.
When a red blood cell is placed in an isotonic solution neither the solvent moves out of the cell nor enters into the cell.
When it is placed in a hypotonic solution, the solvent from the solution enters into the cell (Endosmosis).
When it is placed inside a hypertonic solution, the solvent inside the cell goes into the solution (Exosmosis).