**Question 1**

A certain airplane has a speed of 290.0 km/h and is diving at an angle of 26.0° below the horizontal when the pilot releases a radar decoy. The horizontal distance between the release point and the point where the decoy strikes the ground is d=621 m.

a)How long is the decoy in the air? seconds

b) How high was the release point? m. c)A projectile’s launch speed is 7.4 times its speed at maximum height. Find the launch angle θ, measured from the horizontal.

**Question 2**

a certain airplane has a speed of 290.0 km/h

**Question 3**

a certain airplane has a speed of 290.0 km/h

**Answer to question 1**

**Answer to question 2**

Step 1

(a)

The decoy can be considered as a projectile. The equation for the horizontal component of the initial velocity of the decoy is given by,

The decoy will have no acceleration in horizontal direction so that its horizontal velocity will be constant and same as the initial value. The equation for the horizontal distance travelled by the decoy is given by,

Step 2

(b)The equation for the vertical motion of the ball is given by,

Thus,

Thus, the release point is 404.59m high.

**Answer to question 3**

As option D is close to the answer so the correct answer is option D.

And we don’t get an exact value coinciding with the answer may be due to the approximate value used. For example I have used Vx=69.75 but it can be approximated as 70.Therefore the value don’t match.